y(y+1)=y^2-2y-3

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Solution for y(y+1)=y^2-2y-3 equation:


Simplifying
y(y + 1) = y2 + -2y + -3

Reorder the terms:
y(1 + y) = y2 + -2y + -3
(1 * y + y * y) = y2 + -2y + -3
(1y + y2) = y2 + -2y + -3

Reorder the terms:
1y + y2 = -3 + -2y + y2

Add '-1y2' to each side of the equation.
1y + y2 + -1y2 = -3 + -2y + y2 + -1y2

Combine like terms: y2 + -1y2 = 0
1y + 0 = -3 + -2y + y2 + -1y2
1y = -3 + -2y + y2 + -1y2

Combine like terms: y2 + -1y2 = 0
1y = -3 + -2y + 0
1y = -3 + -2y

Solving
1y = -3 + -2y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '2y' to each side of the equation.
1y + 2y = -3 + -2y + 2y

Combine like terms: 1y + 2y = 3y
3y = -3 + -2y + 2y

Combine like terms: -2y + 2y = 0
3y = -3 + 0
3y = -3

Divide each side by '3'.
y = -1

Simplifying
y = -1

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